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1.2.9 Example
A body undergoes a simple harmonic motion with amplitude 3.0 m and period 4.00 s. Find the
a) angular frequency,
b) maximum speed,
c) maximum acceleration,
d) acceleration of the body when it is 1.0 m from the equilibrium point, and
e) speed of the body when it is 1.0 m from the equilibrium point.
[ 1.57 rad/s, 4.7 m/s , 7.4 m/s^2 , -2.5 m/s^2, 4.4 m/s ]
Hint:
1.2.9.1 Solution:
a) angular frequency , ω =
b) maximum speed, v0 = x0ω = (3.00)(1.57) = 0.047 m/sc) maximum acceleration, |a0| = x0ω2 = (3.00)(1.57)2 = 7.4 m/s2
d) when x = 1.00, acceleration, a = -ω2x = (1.57)2(1.00) = -2.5 m/s2
e) when x = 1.00, speed, v = x0ω = (3.00)(1.57) = 4.4 m/s
1.2.9.2 Model:
Translations
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- Details
- Parent Category: 02 Newtonian Mechanics
- Category: 09 Oscillations
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