Project 5: webEJS workshop Balancing Chemistry Equation JavaScript Simulation Applet HTML5 with option 11 and 12 added by Karen - Open Educational Resources / Open Source Physics @ Singapore

{source}

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"modelname" => "webejs_model_Balancing_Chemical_Equations_modified2");

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Sample Learning Goals

{source} <div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/a/AVvXsEg6lcnwp511uMX_f_YsXaWKuumghd4hx5HoM_V18ZfqkxZCkvFp8XnatSeqTuriUMztAvRnEpiJiyTK9xEKy_VCFGSsvtWmcCwt9qxVv3_Eg3CHHZepaCU1rkkn_JVFVEdYwUxdwlKDgOPiQdbzR2xeKXsGDECYXyDh7eTXUPR486Pp5FmQmrym00vRriWA" style="margin-left: 1em; margin-right: 1em;"> </a></div> <h3>Educational Simulation for Balancing Chemical Equations Using Easy JavaScript Simulation Toolkit</h3>Balancing chemical equations is a fundamental skill in chemistry, and mastering it can sometimes be challenging for students. To address this, an interactive simulation was developed using the Easy JavaScript Simulation (EJS) toolkit. This simulation offers a visually engaging and hands-on approach to learning how to balance chemical equations, making the learning process both effective and enjoyable.<h4>Key Features</h4><ol><li>Interactive Interface:<ul><li>The simulation provides an intuitive interface where students can manipulate coefficients to balance chemical equations. The real-time feedback helps students immediately see the effects of their changes.</li></ul></li><li>Step-by-Step Guidance:<ul><li>The simulation offers step-by-step guidance, helping students understand the process of balancing chemical equations. It breaks down the task into manageable parts, making it easier to grasp complex concepts.</li></ul></li><li>Visual Representation:<ul><li>Each chemical equation is represented with visual molecules, allowing students to see the atoms involved in the reaction. This visual aid helps students understand the conservation of mass and the need for balancing equations.</li></ul></li><li>Immediate Feedback:<ul><li>As students adjust the coefficients, the simulation provides immediate feedback on whether the equation is balanced correctly. This instant feedback loop reinforces learning and helps students correct mistakes in real-time.</li></ul></li><li>Progress Tracking:<ul><li>The simulation tracks the progress of students through different questions, showing which equations have been balanced correctly and which ones need more work. This feature helps students monitor their learning journey.</li></ul></li><li>Multiple Equations:<ul><li>The simulation includes a variety of chemical equations, ranging from simple to complex. This diversity ensures comprehensive practice and helps students become proficient in balancing different types of equations.</li></ul></li></ol><h4>Benefits of the Simulation</h4><ul><li>Enhanced Understanding:
The interactive nature of the simulation helps students develop a deeper understanding of balancing chemical equations. By manipulating coefficients and seeing the immediate impact, students can better grasp the concept of conservation of mass.</li><li>Engaging Learning Experience:
The visually appealing and interactive design makes learning more engaging and enjoyable. Students are more likely to stay motivated and interested in the subject matter.</li><li>Active Learning:
The simulation promotes active learning by encouraging students to experiment with different coefficients and see the results. This hands-on approach helps reinforce theoretical concepts through practical application.</li><li>Accessibility:
The Easy JavaScript Simulation toolkit allows for the creation of web-based simulations that can be accessed from anywhere with an internet connection. This makes the tool accessible to a wide audience of learners.</li></ul><h4>Example: Balancing Fe₂O₃ + CO → Fe + CO₂</h4>In one of the simulations, students are presented with the equation:<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mtext>CO</mtext><mo>→</mo></mrow></semantics></math>Fe+CO2To balance this equation, students need to ensure that the number of each type of atom on the reactant side is equal to the number on the product side. Through the simulation, students can:<ul><li>Adjust the coefficients of each compound.</li><li>Visually see the number of atoms represented by colored balls.</li><li>Receive feedback on whether their adjustments have balanced the equation.</li></ul>For instance, the balanced equation is:<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mn>3</mn><mtext>CO</mtext><mo>→</mo></mrow></semantics></math>2Fe+3CO2This process helps students understand how to balance not only this equation but also provides a methodology for tackling any chemical equation they encounter.<h4>Conclusion</h4>This simulation for balancing chemical equations, built using the Easy JavaScript Simulation toolkit, is a powerful educational tool. It transforms a traditionally challenging topic into an interactive and engaging learning experience. By providing immediate feedback, visual aids, and step-by-step guidance, the simulation enhances students' understanding and mastery of balancing chemical equations. This innovative approach to learning chemistry is an excellent example of how technology can be leveraged to improve education. New Option added by KarenThe chemical equation provided in the simulation is:<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/a/AVvXsEhu_uUDAZI8qdvDBvRFanGWWdafqvjgFZJchxem-mz1beYOR3dpkTp6nKyb8EDNdq3zVT10ghvW9Nt5YFbLH426QIdCNqNTByfZSCUsuG8tx66k7-XmwhDlx5ksbl5_BeYLAPYhIlhJ-8MXhafMq2Nerwv3Hi8cr-8u-tTJ9Uo7Ll9fioztsXfDoVtwp09S" style="margin-left: 1em; margin-right: 1em;"><img alt="" data-original-height="908" data-original-width="1888" height="308" src="https://blogger.googleusercontent.com/img/a/AVvXsEhu_uUDAZI8qdvDBvRFanGWWdafqvjgFZJchxem-mz1beYOR3dpkTp6nKyb8EDNdq3zVT10ghvW9Nt5YFbLH426QIdCNqNTByfZSCUsuG8tx66k7-XmwhDlx5ksbl5_BeYLAPYhIlhJ-8MXhafMq2Nerwv3Hi8cr-8u-tTJ9Uo7Ll9fioztsXfDoVtwp09S=w640-h308" width="640" /></a></div> <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>?? Cu(NO</mtext><mn>3</mn></msub><msub><mtext>)</mtext><mn>2</mn></msub><mo>→</mo></mrow></semantics></math>CuO+NO2+O2 ??To balance this equation, we need to ensure that the number of each type of atom on the reactant side is equal to the number on the product side.<h3>Step-by-Step Solution</h3><ol><li>Write down the number of each type of atom in the reactants and products:<ul><li>Reactants:<ul><li>Cu: 1</li><li>N: 2</li><li>O: 6</li></ul></li><li>Products:<ul><li>Cu: 1</li><li>N: 1</li><li>O: (1 in CuO) + (2 in NO₂) + (2 in O₂) = 5</li></ul></li></ul></li><li>Balance the nitrogen (N) atoms:<ul><li>To balance the nitrogen atoms, we need 2 NO₂ molecules on the product side:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Cu(NO</mtext><mn>3</mn></msub><msub><mtext>)</mtext><mn>2</mn></msub><mo>→</mo><mtext>CuO</mtext><mo>+</mo><mn>2</mn><msub><mtext>NO</mtext><mn>2</mn></msub><mo>+</mo><msub><mtext>O</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{Cu(NO}_3\text{)}_2 \rightarrow \text{CuO} + 2\text{NO}_2 + \text{O}_2</annotation></semantics></math>Cu(NO3)2→CuO+2NO2+O2</li></ul></li><li>Recount the number of each type of atom:<ul><li>Reactants:<ul><li>Cu: 1</li><li>N: 2</li><li>O: 6</li></ul></li><li>Products:<ul><li>Cu: 1</li><li>N: 2</li><li>O: (1 in CuO) + (4 in 2NO₂) + (2 in O₂) = 7</li></ul></li></ul></li><li>Balance the oxygen (O) atoms:<ul><li>We now have 6 oxygens in the reactants and 7 in the products. Therefore, we need to add another half O₂ molecule to the product side:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Cu(NO</mtext><mn>3</mn></msub><msub><mtext>)</mtext><mn>2</mn></msub><mo>→</mo><mtext>CuO</mtext><mo>+</mo><mn>2</mn><msub><mtext>NO</mtext><mn>2</mn></msub><mo>+</mo><mfrac><mn>1</mn><mn>2</mn></mfrac><msub><mtext>O</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{Cu(NO}_3\text{)}_2 \rightarrow \text{CuO} + 2\text{NO}_2 + \frac{1}{2}\text{O}_2</annotation></semantics></math>Cu(NO3)2→CuO+2NO2+21O2</li></ul></li><li>Adjust coefficients to ensure all atoms are balanced:<ul><li>Since we cannot have a fraction of a molecule in the final balanced equation, we multiply all coefficients by 2:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mn>2</mn><msub><mtext>Cu(NO</mtext><mn>3</mn></msub><msub><mtext>)</mtext><mn>2</mn></msub><mo>→</mo><mn>2</mn><mtext>CuO</mtext><mo>+</mo><mn>4</mn><msub><mtext>NO</mtext><mn>2</mn></msub><mo>+</mo><msub><mtext>O</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">2\text{Cu(NO}_3\text{)}_2 \rightarrow 2\text{CuO} + 4\text{NO}_2 + \text{O}_2</annotation></semantics></math>2Cu(NO3)2→2CuO+4NO2+O2</li></ul></li></ol><h3>Balanced Equation</h3>The balanced chemical equation is:<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mn>2</mn><msub><mtext>Cu(NO</mtext><mn>3</mn></msub><msub><mtext>)</mtext><mn>2</mn></msub><mo>→</mo><mn>2</mn><mtext>CuO</mtext><mo>+</mo><mn>4</mn><msub><mtext>NO</mtext><mn>2</mn></msub><mo>+</mo><msub><mtext>O</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">2\text{Cu(NO}_3\text{)}_2 \rightarrow 2\text{CuO} + 4\text{NO}_2 + \text{O}_2</annotation></semantics></math>2Cu(NO3)2→2CuO+4NO2+O2<a href="https://blogger.googleusercontent.com/img/a/AVvXsEj1yMQRIhuQQ5QdA2bo2J_aptvxTV73UHZMrilO2xkRsR7m5s5cSEnjkt3TQvrPMI3nOqikUChciqZa87kptFkrz3VT-hSEcRvgwibSXfJNJJfssqTBP1eAGJun6ssGpbRdPEK8Xpwiomto7piv9H4mTH25aPALMC1d9Xmcjmoi2Pf6BHCGyHGFMkF9vd6K" style="margin-left: 1em; margin-right: 1em; text-align: center;"><img alt="" data-original-height="922" data-original-width="1902" height="310" src="https://blogger.googleusercontent.com/img/a/AVvXsEj1yMQRIhuQQ5QdA2bo2J_aptvxTV73UHZMrilO2xkRsR7m5s5cSEnjkt3TQvrPMI3nOqikUChciqZa87kptFkrz3VT-hSEcRvgwibSXfJNJJfssqTBP1eAGJun6ssGpbRdPEK8Xpwiomto7piv9H4mTH25aPALMC1d9Xmcjmoi2Pf6BHCGyHGFMkF9vd6K=w640-h310" width="640" /></a>This balanced equation ensures that the number of atoms of each element is the same on both sides of the reaction. option12<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/a/AVvXsEhvd8915OU3IB6oHUG6R0_vRWk54CdoV7Qy_Os1jiMEL0lN8t9zBedKp73QHIMYX6c-ono4HhYKO9MRLN1U0dkEBtoLbIEa707sWwZpqk1Fw3qerdm-js7-5Rn8ObZ-fWYRKV-MN3zvRxoazYJu867tC4l9zV1bqpRFEhKwuhz-YuK_f2GESpLxKQJaEHTY" style="margin-left: 1em; margin-right: 1em;"><img alt="" data-original-height="920" data-original-width="1891" height="312" src="https://blogger.googleusercontent.com/img/a/AVvXsEhvd8915OU3IB6oHUG6R0_vRWk54CdoV7Qy_Os1jiMEL0lN8t9zBedKp73QHIMYX6c-ono4HhYKO9MRLN1U0dkEBtoLbIEa707sWwZpqk1Fw3qerdm-js7-5Rn8ObZ-fWYRKV-MN3zvRxoazYJu867tC4l9zV1bqpRFEhKwuhz-YuK_f2GESpLxKQJaEHTY=w640-h312" width="640" /></a></div> The chemical equation provided in the simulation is:<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mtext>CO</mtext><mo>→</mo><mtext>Fe</mtext><mo>+</mo><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{Fe}_2\text{O}_3 + \text{CO} \rightarrow \text{Fe} + \text{CO}_2</annotation></semantics></math>Fe2O3+CO→Fe+CO2To balance this equation, we need to ensure that the number of each type of atom on the reactant side is equal to the number on the product side.<h3>Step-by-Step Solution</h3><ol><li>Write down the number of each type of atom in the reactants and products:<ul><li>Reactants:<ul><li>Fe: 2</li><li>O: 4 (3 from <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub></mrow><annotation encoding="application/x-tex">\text{Fe}_2\text{O}_3</annotation></semantics></math>Fe2O3 and 1 from <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mtext>CO</mtext></mrow><annotation encoding="application/x-tex">\text{CO}</annotation></semantics></math>CO)</li><li>C: 1</li></ul></li><li>Products:<ul><li>Fe: 1</li><li>O: 2 (from <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{CO}_2</annotation></semantics></math>CO2)</li><li>C: 1</li></ul></li></ul></li><li>Balance the iron (Fe) atoms:<ul><li>We need 2 Fe atoms on the product side to match the 2 Fe atoms on the reactant side:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mtext>CO</mtext><mo>→</mo><mn>2</mn><mtext>Fe</mtext><mo>+</mo><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{Fe}_2\text{O}_3 + \text{CO} \rightarrow 2\text{Fe} + \text{CO}_2</annotation></semantics></math>Fe2O3+CO→2Fe+CO2</li></ul></li><li>Recount the number of each type of atom:<ul><li>Reactants:<ul><li>Fe: 2</li><li>O: 4</li><li>C: 1</li></ul></li><li>Products:<ul><li>Fe: 2</li><li>O: 2 (from <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{CO}_2</annotation></semantics></math>CO2)</li><li>C: 1</li></ul></li></ul></li><li>Balance the oxygen (O) atoms:<ul><li>We have 4 oxygens in the reactants and 2 in the products. We need more oxygen atoms on the product side. Each <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{CO}_2</annotation></semantics></math>CO2 molecule adds 2 oxygens, so we need more <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{CO}_2</annotation></semantics></math>CO2 molecules:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mn>3</mn><mtext>CO</mtext><mo>→</mo><mn>2</mn><mtext>Fe</mtext><mo>+</mo><mn>3</mn><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2</annotation></semantics></math>Fe2O3+3CO→2Fe+3CO2</li></ul></li><li>Recount the number of each type of atom:<ul><li>Reactants:<ul><li>Fe: 2</li><li>O: 6 (3 from 3 <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mtext>CO</mtext></mrow><annotation encoding="application/x-tex">\text{CO}</annotation></semantics></math>CO)</li><li>C: 3</li></ul></li><li>Products:<ul><li>Fe: 2</li><li>O: 6 (from 3 <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>CO</mtext><mn>2</mn></msub></mrow><annotation encoding="application/x-tex">\text{CO}_2</annotation></semantics></math>CO2)</li><li>C: 3</li></ul></li></ul></li></ol><h3>Balanced Equation</h3>The balanced chemical equation is:<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><msub><mtext>Fe</mtext><mn>2</mn></msub><msub><mtext>O</mtext><mn>3</mn></msub><mo>+</mo><mn>3</mn><mtext>CO</mtext></mrow></semantics></math>→2Fe+3CO2This balanced equation ensures that the number of atoms of each element is the same on both sides of the reaction.<a href="https://blogger.googleusercontent.com/img/a/AVvXsEj0R67V_CUumuC34pK3n5bhRb6Tn3lDKLNCw6PJxyV9i0doA6hIm026aZG9KYnewlWPfiofgQ5LHsEzYsVsFKcAx1_hVJMLs6RmO_Y8N02B_pyDlnvv-9VG7MdwTfkCUXI6hkjFmPdrj56uLQVnmz9PFFBxO5YeoCYFMBAkXPewThwR-4Gkmr557hmKPg3d" style="margin-left: 1em; margin-right: 1em; text-align: center;"><img alt="" data-original-height="915" data-original-width="1903" height="308" src="https://blogger.googleusercontent.com/img/a/AVvXsEj0R67V_CUumuC34pK3n5bhRb6Tn3lDKLNCw6PJxyV9i0doA6hIm026aZG9KYnewlWPfiofgQ5LHsEzYsVsFKcAx1_hVJMLs6RmO_Y8N02B_pyDlnvv-9VG7MdwTfkCUXI6hkjFmPdrj56uLQVnmz9PFFBxO5YeoCYFMBAkXPewThwR-4Gkmr557hmKPg3d=w640-h308" width="640" /></a>{/source}

For Teachers

20240718-24 Web EJS beta Workshop by Francisco Esquembre and Félix J. García Clemente supported by MOE CPDD1 Registration for Web EJS Workshop (18-24 July 2024)

Dates: July 18th-24th, 2024
Venue: MOEHQ Buona Vista, B3-02 (18 July) P2-01-02 (19,22,23,24 July) or
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Trainers are:

Full Professor Francisco Esquembre

Full Professor Félix J. García Clemente

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Details: Written by: Loo Kang Wee; Parent Category: Interactive Resources; Category: Chemistry; Published: 30 July 2024; Created: 30 July 2024; Last Updated: 13 August 2024; Hits: 3487

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